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Capacitors in series and parallel: total capacitance, charge and energy

Calculate the total capacitance of up to four capacitors in series or in parallel, with the charge and energy stored at a given voltage.

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Results

Total capacitance in parallel

79.000 µF

Total capacitance in series

5.998 µF

Charge stored in parallel
948.00 µC
Charge stored in series
71.97 µC
Energy stored in parallel
5.6880 mJ
Energy stored in series
0.4318 mJ

Combining capacitors

When a single capacitor of the right value is not available, or you need a higher voltage rating, you combine several. The rules are the mirror image of the rules for resistors.

In parallel, the capacitances add:

C = C₁ + C₂ + C₃ + …

In series, the reciprocals add:

1 ÷ C = 1 ÷ C₁ + 1 ÷ C₂ + 1 ÷ C₃ + …

A series combination is always smaller than the smallest capacitor in it. Enter 0 for any position you do not use; the calculator ignores it.

Charge and energy

The calculator also uses the voltage across the whole combination to find:

  • the charge stored, Q = C × V
  • the energy stored, E = ½ × C × V²

With capacitance in microfarads, the charge comes out in microcoulombs, and the energy is shown in millijoules.

Worked example

Three capacitors of 10 µF, 22 µF and 47 µF at 12 V:

Parallel Series
Total capacitance 79 µF 5.998 µF
Charge 948 µC 71.97 µC
Energy 5.688 mJ 0.4318 mJ

The parallel bank stores more than 13 times the energy of the series string at the same voltage.

Why use series at all?

The main reason is voltage. Each capacitor in a series string carries the same charge, so the total voltage divides between them in inverse proportion to their capacitance: V₁ = Q ÷ C₁. In the example, the 10 µF capacitor takes 7.2 V, the 22 µF one 3.3 V and the 47 µF one 1.5 V. Two identical capacitors in series split the voltage evenly, which lets you build a 50 V part from two 25 V ones. In practice, balancing resistors are placed across each capacitor because leakage currents are never exactly equal.

Why the rules are reversed

The capacitance of a plate capacitor is C = ε × A ÷ d. Putting capacitors in parallel effectively adds plate area A, so capacitance adds. Putting them in series effectively adds plate spacing d, so the reciprocals add. Resistors do the opposite because resistance grows with length and falls with cross-section.

Practical notes

Electrolytic capacitors have wide tolerances, often ±20%, so the real total can differ noticeably from the nominal value. Polarized capacitors must be connected the right way round in both arrangements, and the voltage rating of a parallel bank is that of its weakest member.

Frequently asked questions

How do capacitors add in parallel?

In parallel the capacitances simply add: 10 µF + 22 µF + 47 µF = 79 µF. Every capacitor sees the same voltage, so the bank stores more charge.

How do capacitors add in series?

In series you add the reciprocals: 1 ÷ C = 1 ÷ C₁ + 1 ÷ C₂ + … The total is always smaller than the smallest capacitor. 10, 22 and 47 µF in series give about 6.0 µF.

Why is this the opposite of resistors?

Resistors add in series and combine by reciprocals in parallel. Capacitors do the reverse because capacitance grows with plate area (parallel adds area) and shrinks with plate spacing (series adds spacing).

What voltage does each capacitor see in series?

Each capacitor in a series string holds the same charge, so the voltage splits in inverse proportion to capacitance: the smallest capacitor takes the largest share. Check that share against each part's voltage rating.

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Results are estimates provided for information purposes. They do not replace professional advice.