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Freezing point depression and boiling point elevation calculator

Calculate how much a dissolved solute lowers the freezing point and raises the boiling point of a solvent, with the van 't Hoff factor.

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Results

Freezing point depression ΔTf

3.72 °C

New freezing point

-3.72 °C

Boiling point elevation ΔTb
1.024 °C
New boiling point
101.02 °C
Molality
1 mol/kg
New freezing point in °F
25.3 °F

Freezing point at other solute masses

New freezing pointNew boiling point
10 g current-0.64100.18
25 g current-1.59100.44
50 g current-3.18100.88
100 g current-6.37101.75
150 g current-9.55102.63
200 g current-12.73103.50
250 g current-15.91104.38

Colligative properties

Dissolving a solute in a solvent lowers its freezing point and raises its boiling point. These changes, called colligative properties, depend on the number of dissolved particles, not on what they are. That is why salt melts ice on roads, why antifreeze protects car engines and why seawater freezes at about −1.9 °C instead of 0 °C.

The formulas

  • Freezing point depression: ΔTf = i × Kf × m
  • Boiling point elevation: ΔTb = i × Kb × m
  • Molality: m = moles of solute ÷ kg of solvent

Kf and Kb are constants of the solvent, in °C·kg/mol, and i is the van ’t Hoff factor, the number of particles each formula unit releases in solution.

Worked example

Dissolve 58.44 g of sodium chloride (1 mol) in 1 kg of water. NaCl splits into Na⁺ and Cl⁻, so i = 2.

  1. m = 1.00 mol ÷ 1.00 kg = 1.00 mol/kg.
  2. ΔTf = 2 × 1.86 × 1.00 = 3.72 °C: the water now freezes at −3.72 °C (25.3 °F).
  3. ΔTb = 2 × 0.512 × 1.00 = 1.024 °C: it boils at 101.02 °C.

Freezing point at other amounts of salt (1 kg of water)

NaCl added Freezing point Boiling point
10 g −0.64 °C 100.18 °C
50 g −3.18 °C 100.88 °C
100 g −6.37 °C 101.75 °C
200 g −12.73 °C 103.50 °C

At high concentrations, the real depression is somewhat smaller, because ions pair up and the ideal formula no longer holds exactly. A saturated brine bottoms out at about −21 °C.

Solvent constants

Solvent Freezing point Kf Boiling point Kb
Water 0 °C 1.86 100 °C 0.512
Benzene 5.5 °C 5.12 80.1 °C 2.53
Cyclohexane 6.5 °C 20.0 80.7 °C 2.79
Ethanol −114.1 °C 1.99 78.4 °C 1.22
Acetic acid 16.6 °C 3.90 118.1 °C 3.07

Measuring molar mass

Before mass spectrometry, chemists found molar masses by cryoscopy: dissolve a known mass in a solvent with a large Kf, such as cyclohexane or camphor, measure ΔTf, and solve for the number of moles.

Road salt and antifreeze

Rock salt works well down to about 15 °F (−9 °C) on roads; below that, calcium chloride (i = 3) is used. Car antifreeze uses ethylene glycol, a molecular solute (i = 1): a 50/50 mix with water protects to about −37 °C, more than the simple formula predicts for such a concentrated solution, which is outside its ideal range.

Frequently asked questions

How do you calculate freezing point depression?

ΔTf = i × Kf × m, where i is the van 't Hoff factor, Kf the solvent's cryoscopic constant and m the molality. One mole of NaCl in 1 kg of water lowers the freezing point by 2 × 1.86 × 1 = 3.72 °C.

What is the van 't Hoff factor?

The number of particles each formula unit gives in solution: 1 for sugar, 2 for NaCl, 3 for CaCl₂. Real values are slightly lower in concentrated solutions because ions pair up.

Why is salt spread on icy roads?

Dissolved salt lowers the freezing point of water, so ice melts below 32 °F. Rock salt works down to about 15 °F in practice; calcium chloride works at much lower temperatures.

Does salt make water boil faster?

No. Salt raises the boiling point slightly, by about 0.5 °C per mole of particles per kilogram of water, so a pinch in pasta water makes no measurable difference.

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Results are estimates provided for information purposes. They do not replace professional advice.