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Graham's law: which gas escapes faster, and by how much?

Compare the effusion rates of two gases from their molar masses, convert a known effusion time from one gas to the other, and see the average speed of their molecules.

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Results

Effusion rate of gas 1 ÷ rate of gas 2

3.984

Gas 1 is lighter and escapes faster
Time for the same amount of gas 1 to escape
15.06
Effusion rate of gas 2 ÷ rate of gas 1
0.251
RMS speed of gas 1 molecules √(3RT/M)
1,904
RMS speed of gas 2 molecules
478

Why helium balloons go flat first

Fill one balloon with helium and another with air, and the helium balloon shrinks first. Small helium atoms move faster and slip through tiny gaps more often than the heavier nitrogen and oxygen molecules in air. Thomas Graham measured this effect in the 1840s and found a simple rule.

The law

rate₁ ÷ rate₂ = √(M₂ ÷ M₁)

where M₁ and M₂ are the molar masses of the two gases. Because time is the inverse of rate, the time for the same amount of gas to escape follows the opposite ratio:

time₁ ÷ time₂ = √(M₁ ÷ M₂)

Where it comes from

At a given temperature, every gas has the same average kinetic energy per molecule, ½mv². If m is smaller, v must be larger. The root-mean-square speed is:

v_rms = √(3RT ÷ M)

with R = 8.314 J/(mol·K), T in kelvins and M in kg/mol. Hydrogen at 68 °F moves at about 1,900 m/s; oxygen at about 480 m/s.

Example

Compare hydrogen (2.016 g/mol) with oxygen (32.00 g/mol):

  • Rate ratio: √(32.00 ÷ 2.016) = 3.98, so hydrogen escapes about four times faster.
  • If a given amount of oxygen takes 60 seconds to escape through a pinhole, the same amount of hydrogen takes 60 ÷ 3.98 ≈ 15 seconds.

Using it to find an unknown molar mass

Measure the effusion time of an unknown gas and of a known gas through the same opening under the same conditions. Then M_unknown = M_known × (t_unknown ÷ t_known)². This was one of the early methods to estimate molar masses.

Limits

Graham’s law is exact only for effusion through holes much smaller than the distance molecules travel between collisions, and only when both gases are at the same temperature and pressure. Leaks through rubber or plastic also depend on how the gas dissolves in the material, so balloons are a good illustration but not a precise test.

Frequently asked questions

What is Graham's law?

The rate at which a gas escapes through a tiny hole (effusion) is inversely proportional to the square root of its molar mass: rate₁ ÷ rate₂ = √(M₂ ÷ M₁). Scottish chemist Thomas Graham published it in the 1840s.

Why do lighter gases escape faster?

At the same temperature, all gas molecules have the same average kinetic energy, ½mv². Lighter molecules must therefore move faster, so they hit the hole more often. Hydrogen molecules move about four times faster than oxygen molecules.

What is the difference between effusion and diffusion?

Effusion is the escape of gas through a hole smaller than the distance molecules travel between collisions. Diffusion is the gradual mixing of gases. Graham's law is exact for effusion and only approximate for diffusion.

How was Graham's law used to enrich uranium?

Uranium hexafluoride made with uranium-235 is about 0.43% faster than the uranium-238 version, because their molar masses are 349 and 352 g/mol. The gaseous diffusion plants of the 1940s to 2010s pushed the gas through thousands of porous barriers in a row to build up that tiny difference.

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Results are estimates provided for information purposes. They do not replace professional advice.