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Hall effect: voltage across a conductor in a magnetic field

Calculate the Hall voltage, the Hall coefficient, the Hall field and the drift velocity of charge carriers in a metal or semiconductor strip carrying a current in a magnetic field.

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Results

Hall voltage

7.352

Hall coefficient 1 ÷ (nq)
7.352 × 10⁻¹¹ m³/C
Hall electric field
0.0007352 V/m
Drift velocity of the carriers
0.0007352 m/s
Carrier density used
8.49 × 10²⁸ m⁻³

A sideways voltage from a magnetic field

In 1879, Edwin Hall, then a graduate student at Johns Hopkins, passed a current through a thin gold leaf placed between the poles of a magnet and measured a tiny voltage across the leaf, at right angles to both the current and the field. The moving charges are pushed sideways by the magnetic force until the charge that piles up on one edge creates an electric field strong enough to balance it. That equilibrium voltage is the Hall voltage.

The formulas

  • Hall voltage: V = I × B ÷ (n × q × t)
  • Hall coefficient: R_H = 1 ÷ (n × q), in m³/C
  • Hall field: E = V ÷ w
  • Drift velocity of the carriers: v = I ÷ (n × q × w × t)

Here I is the current, B the magnetic field, n the number of charge carriers per cubic meter, q the elementary charge (1.602 × 10⁻¹⁹ C), t the thickness of the strip along the field and w its width, across which the voltage is measured.

Example: a copper strip

A copper strip 10 mm wide and 0.1 mm thick carries 10 A in a 1 T field. Copper has about 8.49 × 10²⁸ free electrons per m³:

  • Hall voltage: 10 × 1 ÷ (8.49 × 10²⁸ × 1.602 × 10⁻¹⁹ × 0.0001) = 7.35 µV
  • Hall coefficient: 7.35 × 10⁻¹¹ m³/C
  • Drift velocity: 0.74 mm/s, slower than a snail, even with 10 A flowing

Choose indium antimonide, with about 2 × 10²² carriers per m³, and a current of only 10 mA gives about 31 mV in the same field: four million times fewer carriers make the effect four million times larger per ampere. This is why Hall sensors are made from semiconductors, not metals.

Reading the result

  • The voltage is proportional to the current and to the field, which is what makes Hall probes good magnetometers once calibrated.
  • It is inversely proportional to the thickness, so sensors use very thin films.
  • The sign of the voltage tells whether the carriers are negative electrons or positive holes, which showed in the 1930s that some metals and doped semiconductors conduct by holes.

Limits

The simple formula assumes a single type of carrier. In semiconductors with both electrons and holes, or in metals such as zinc or beryllium, the measured coefficient mixes the two and its sign can be surprising. At very low temperature and very high field, the quantum Hall effect appears, in which the resistance takes exact values h ÷ (ie²), now used as the standard of electrical resistance.

Frequently asked questions

What is the Hall effect?

When a current flows through a conductor placed in a magnetic field perpendicular to it, the Lorentz force pushes the moving charges to one side. A small voltage, the Hall voltage, builds up across the width of the conductor. Edwin Hall discovered it in 1879.

Why is the Hall voltage so small in copper?

Because copper has about 8.5 × 10²⁸ free electrons per cubic meter. The more carriers there are, the slower they drift for a given current and the weaker the sideways push. Semiconductors such as indium antimonide have far fewer carriers, so their Hall voltage is millions of times larger.

What is the Hall coefficient used for?

R_H = 1 ÷ (nq) gives the carrier density and, by its sign, the type of carrier: negative for electrons, positive for holes. Measuring it is a standard way to characterize semiconductor samples.

Where are Hall sensors used?

In phones (compass), car wheel speed and crankshaft sensors, brushless motors, current clamps, keyboards and door switches. They measure magnetic fields without contact, which makes them reliable and cheap.

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Results are estimates provided for information purposes. They do not replace professional advice.