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Rydberg equation: wavelength of hydrogen spectral lines

Calculate the wavelength, frequency and photon energy of the light emitted when an electron drops between two energy levels of hydrogen or a hydrogen-like ion.

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Wavelength (in vacuum)

656.47 nm

Visible light

Photon energy

1.8887 eV

Frequency
456.67 THz
Series (by lower level)
2
Balmer
Series limit (n₂ → ∞)
364.71 nm
Energy to ionize from level n₁
3.3996 eV

The barcode of hydrogen

Pass the light of a glowing hydrogen tube through a prism and instead of a rainbow you see a few sharp colored lines: red, blue-green, violet. In 1885 the Swiss schoolteacher Johann Balmer found a formula that matched their wavelengths. In 1888 the Swedish physicist Johannes Rydberg generalized it to all of hydrogen’s lines, and in 1913 Niels Bohr explained it: each line is a photon emitted when the electron drops from one energy level to a lower one.

The formula

1/λ = R × Z² × (1/n₁² − 1/n₂²)

  • λ is the wavelength in vacuum.
  • n₁ is the lower level and n₂ the upper level, with n₂ > n₁.
  • Z is the nuclear charge: 1 for hydrogen and deuterium, 2 for He⁺, 3 for Li²⁺.
  • R is the Rydberg constant corrected for the mass of the nucleus. For an infinitely heavy nucleus, R∞ = 10,973,731.568 m⁻¹; for hydrogen it is about 10,967,758 m⁻¹.

The photon energy is E = hc ÷ λ, which is 1239.84 ÷ λ in nanometers, in electronvolts.

Worked example: H-alpha

For hydrogen, n₂ = 3 to n₁ = 2:

  • 1/λ = 10,967,758 × (1/4 − 1/9) = 1,523,300 m⁻¹.
  • Wavelength: 656.47 nm in vacuum, a deep red.
  • Photon energy: 1.889 eV; frequency 456.67 THz.
  • The Balmer series converges to a limit of 364.71 nm as n₂ grows.
  • Ionizing the atom from level 2 takes 3.40 eV.

The series

Lower level Series Region First line
1 Lyman Ultraviolet 121.6 nm
2 Balmer Visible and near UV 656.5 nm
3 Paschen Infrared 1,875 nm
4 Brackett Infrared 4,051 nm
5 Pfund Infrared 7,460 nm

The four visible Balmer lines are H-alpha (656 nm, red), H-beta (486 nm, blue-green), H-gamma (434 nm, violet) and H-delta (410 nm, violet).

Why it matters

The red glow of nebulae photographed by amateur astronomers is H-alpha light. Astronomers measure the shift of hydrogen lines to find how fast galaxies move. The tiny difference between hydrogen and deuterium lines, about 0.18 nm for H-alpha, is how Harold Urey discovered deuterium in 1931.

Limits

The formula is exact only for one-electron systems. For atoms with several electrons, the inner electrons screen the nucleus and the levels shift. Very fine effects, such as the fine structure and the Lamb shift, split each line into components a fraction of a picometer apart. Tables often list wavelengths in air, which are about 0.03% shorter than the vacuum values given here.

Frequently asked questions

What is the Rydberg formula?

1/λ = R Z² (1/n₁² − 1/n₂²). It gives the wavelength of light emitted when the electron of a hydrogen atom, or a hydrogen-like ion with one electron, drops from level n₂ to level n₁. Johannes Rydberg published it in 1888, generalizing Johann Balmer's 1885 formula for the visible lines.

What is the Rydberg constant?

R∞ = 10,973,731.568 m⁻¹ for an infinitely heavy nucleus. Real nuclei move a little, so the calculator corrects it with the reduced mass: for hydrogen, R_H is about 10,967,758 m⁻¹. This correction is why deuterium lines are shifted slightly, which led to the discovery of deuterium in 1931.

What are the hydrogen series?

Lines ending on level 1 form the Lyman series in the ultraviolet, on level 2 the Balmer series, mostly visible, on level 3 the Paschen series in the infrared, then Brackett, Pfund and Humphreys further into the infrared.

Why is H-alpha 656.47 nm here but 656.28 nm in some tables?

The calculator gives wavelengths in vacuum. Light travels slightly slower in air, so wavelengths measured in air are about 0.03% shorter. Astronomy filters for the red H-alpha line are usually labeled 656.3 nm.

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Results are estimates provided for information purposes. They do not replace professional advice.