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Beam deflection calculator: simply supported beam under a uniform load

Estimate how much a wood or steel beam sags under an evenly spread load, compare it with the usual L/360 limit and see the bending stress.

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Results

Maximum deflection (midspan)

0.207

Within the limit The beam sags less than the chosen limit.
Allowed deflection
0.400
Deflection as span ratio (L/…)
696
Maximum bending stress
707
Maximum bending moment
1,260.00
Moment of inertia
99

Deflection for other spans

Maximum deflection (midspan)Deflection as span ratio (L/…)
8 ft current0.0412,349
10 ft current0.1001,203
12 ft current0.207696
14 ft current0.383438
16 ft current0.654294

What deflection means

Every beam bends under load. Deflection is how far it sags at its weakest point, the middle of the span. A beam can be strong enough not to break and still sag too much: floors that bounce, cracked drywall ceilings and doors that stick are deflection problems. Codes therefore limit deflection to a fraction of the span, such as L/360 for floors. This calculator estimates the deflection of a simply supported rectangular beam under an evenly spread load, compares it with the limit you choose, and gives the bending stress.

The formulas

For a beam resting on two supports with a uniform load w along its span L:

  • Maximum deflection = 5 × w × L⁴ ÷ (384 × E × I)
  • Moment of inertia of a rectangle: I = width × depth³ ÷ 12
  • Maximum bending moment = w × L² ÷ 8
  • Maximum bending stress = moment ÷ (width × depth² ÷ 6)

E is the modulus of elasticity: about 1.6 million psi for Douglas fir-larch No. 2, 1.4 million for spruce-pine-fir, 2.0 million for LVL and 29 million for steel.

Worked example: a floor joist

A 2 × 10 Douglas fir joist (actual size 1.5 × 9.25 in) spans 12 ft and carries 70 lb per foot, roughly 40 psf of live load and 10 psf of dead load at 16 in on center.

  1. I = 1.5 × 9.25³ ÷ 12 = 98.9 in⁴.
  2. Deflection = 5 × 70 × 12⁴ ÷ (384 × E × I), with units converted: 0.21 in, or L/696.
  3. The L/360 limit for 12 ft is 144 ÷ 360 = 0.40 in, so the joist passes comfortably.
  4. Bending moment: 70 × 12² ÷ 8 = 1,260 lb·ft, giving a stress of about 707 psi, below the roughly 900 psi reference design value for No. 2 Douglas fir before code adjustments.

Why span and depth dominate

Deflection grows with the fourth power of the span. For the same joist and load:

Span Deflection Ratio
8 ft 0.04 in L/2,349
10 ft 0.10 in L/1,203
12 ft 0.21 in L/696
14 ft 0.38 in L/438
16 ft 0.65 in L/294

At 16 ft the joist fails L/360. Going to a 2 × 12 would fix it, because stiffness grows with the cube of the depth.

Limits of this calculator

This is a single-span, uniform-load check of a solid rectangular section. It ignores the beam’s own weight, point loads, cantilevers, shear, bearing length, notches, creep and the load duration and size factors that the NDS applies to wood. Use it to compare options and understand trade-offs; for structural changes, follow the span tables in the International Residential Code or have the design checked by an engineer, and get a permit.

Frequently asked questions

How do you calculate beam deflection?

For a simply supported beam with a uniform load, the maximum deflection at midspan is 5wL⁴ ÷ (384EI), where w is the load per length, L the span, E the material's stiffness and I the moment of inertia of the section.

What is L/360?

A deflection limit: the beam may not sag more than its span divided by 360. For a 12 ft span that is 0.4 in. US codes use L/360 for floors under live load and L/240 or L/180 for roofs.

Why does depth matter more than width?

The moment of inertia of a rectangle is width × depth³ ÷ 12. Doubling the width halves the deflection, but doubling the depth cuts it by a factor of eight.

Can I size a beam with this calculator?

Use it to compare options. A real design also checks bending and shear strength, bearing, self-weight, point loads and code adjustments, and structural work usually needs plans approved by your building department.

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Results are estimates provided for information purposes. They do not replace professional advice.