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Omnikalc

Exponential growth calculator: final value, doubling time and half-life

Project a quantity that grows or shrinks by a fixed percentage each period, or continuously, and find how long it takes to double or halve.

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Your inputs

Value out of range

%

Value out of range

Value out of range

Growth model

Results

Value after t periods

1,628.89

Periods to double (growth) or halve (decay)

14.21

Doubling time
Change
628.89
Total change
62.89%
Rule of 70 estimate
14.00
Equivalent continuous rate
4.879%

Value over time

Value after t periodsTotal change
t = 1 current1,050.005.00%
t = 5 current1,276.2827.63%
t = 10 current1,628.8962.89%
t = 20 current2,653.30165.33%
t = 30 current4,321.94332.19%
t = 50 current11,467.401,046.74%

Growth by a fixed percentage

A quantity grows exponentially when it increases by the same percentage each period, rather than by the same amount. Savings with compound interest, a population, the spread of an early epidemic and inflation all follow this pattern. When the percentage is negative, the quantity shrinks the same way: exponential decay describes depreciation, radioactive decay or a drug leaving the body.

The formulas

  • Discrete growth: P(t) = P₀ × (1 + r)ᵗ, with r the rate per period as a decimal
  • Continuous growth: P(t) = P₀ × e^(r × t)
  • Doubling time: ln(2) ÷ ln(1 + r) for discrete growth, ln(2) ÷ r for continuous growth
  • Half-life for decay: ln(2) ÷ |ln(1 + r)|
  • Rule of 70: doubling time ≈ 70 ÷ rate in percent, a quick mental shortcut

Worked example: 1,000 growing 5% a period

  1. After 10 periods: 1,000 × 1.05¹⁰ = 1,628.89, a gain of 62.89%.
  2. Doubling time: ln 2 ÷ ln 1.05 = 14.21 periods.
  3. The rule of 70 gives 70 ÷ 5 = 14, close enough for a quick estimate.
  4. With continuous growth at 5%, the value after 10 periods would be 1,000 × e^0.5 = 1,648.72.

Growth over time at 5%

Periods Value Total change
1 1,050.00 5.00%
5 1,276.28 27.63%
10 1,628.89 62.89%
20 2,653.30 165.33%
30 4,321.94 332.19%
50 11,467.40 1,046.74%

The gain in the second ten periods (1,024) is far larger than in the first ten (629): that acceleration is what makes exponential growth so powerful, and so easy to underestimate.

Decay and half-life

Enter a negative rate for decay. A car losing 15% of its value a year keeps 0.85 each year: after 5 years, 0.85⁵ = 44% of the price remains, and its value halves every ln 2 ÷ |ln 0.85| = 4.3 years. Radioactive isotopes are usually described the other way round, by their half-life: carbon-14 halves every 5,730 years.

Discrete or continuous?

Discrete growth applies the percentage once per period, like interest paid yearly. Continuous growth compounds at every instant and gives a slightly higher result for the same nominal rate. The calculator shows the equivalent continuous rate: 5% per period equals 4.879% compounded continuously.

Limits of the model

Real growth rarely stays exponential for long. Populations run out of resources and markets saturate, which leads to S-shaped, logistic curves. Use exponential projections for short horizons, or as an upper bound.

Frequently asked questions

What is the exponential growth formula?

P(t) = P₀ × (1 + r)ᵗ, where P₀ is the starting value, r the rate per period as a decimal and t the number of periods.

How long does it take to double at 5% a year?

ln(2) ÷ ln(1.05) = 14.2 years. The rule of 70 gives a quick estimate of 70 ÷ 5 = 14 years.

How do I model exponential decay?

Use a negative rate. A value losing 15% a year is multiplied by 0.85 each year and halves in about 4.3 years.

What is the difference between discrete and continuous growth?

Discrete growth applies the rate once per period; continuous growth compounds constantly and uses P₀ × e^(rt). At 5% over 10 periods, 1,000 becomes 1,628.89 or 1,648.72.

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Results are estimates provided for information purposes. They do not replace professional advice.