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Cable sag: tension, length and angle of a hanging cable

Calculate the tension in a cable, rope or wire hanging between two supports at the same height from its span, sag and weight per length.

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Results

Horizontal tension

312.5

Maximum tension, at the supports

313.5

Cable length

100.107

Vertical load on each support
25.0
Cable angle at the supports
4.57 °
Sag ratio (sag ÷ span)
2.00%
Parabolic approximation, accurate for shallow sag

Why a hanging cable pulls so hard

A cable, rope or wire strung between two supports always sags, and the less it sags the harder it pulls on its anchors. Clotheslines, zip lines, guy wires, catenary lighting, fence wires and overhead cables all follow the same simple relationship between span, sag, weight and tension.

The formulas

For a cable with weight w per unit length, span L and sag s at mid-span, with supports at the same height, the parabolic approximation gives:

  • Horizontal tension H = w × L² ÷ (8 × s), the same at every point of the cable
  • Vertical load at each support V = w × L ÷ 2
  • Maximum tension T = √(H² + V²), at the supports
  • Cable length ≈ L + 8s² ÷ (3L)

A point load P hung at mid-span adds P × L ÷ (4s) to the horizontal tension and P ÷ 2 to each vertical reaction. The approximation is accurate as long as the sag stays below about 10% of the span.

Example

A cable weighing 0.5 lb/ft over a 100 ft span with 2 ft of sag:

  • Horizontal tension: 0.5 × 100² ÷ (8 × 2) = 312.5 lbf
  • Vertical load on each support: 25 lbf
  • Maximum tension: 313.5 lbf, at an angle of 4.6° to the horizontal
  • Cable length: 100.11 ft

A 50 lb cable pulls more than 300 lb on each anchor. Halve the sag to 1 ft and the tension doubles to 625 lbf, while the cable gets only about an inch shorter.

Practical points

  • Allow enough sag: a sag of 2 to 5% of the span keeps the tension reasonable.
  • Ice, wind and people pulling on a line add load, so use a safety factor of at least 3 to 5 on the working load of the cable and fittings.
  • Anchors must resist the full tension along the cable direction, not just the weight.
  • Temperature changes the length of metal cables and therefore the sag; a cable tightened in summer sags less and pulls harder in winter.

Frequently asked questions

Why does a tighter cable need so much more tension?

Horizontal tension is H = wL² ÷ 8s, so it is inversely proportional to the sag. Halving the sag doubles the tension. A cable can never be pulled perfectly straight, because the tension would have to be infinite.

Is the parabola accurate or should I use a catenary?

A cable hanging under its own weight forms a catenary, but for sag up to about 10% of the span the parabola gives nearly the same tension and length. For deeper sag, such as a slack chain, use the catenary equations.

Where is the tension highest?

At the supports, where the cable is steepest. There the tension combines the horizontal component, which is the same all along the cable, with the vertical component that carries half the weight.

Can I use this to size a cable or an anchor?

It gives the static tension only. Wind, ice, a person pulling on the line and dynamic loads can multiply it, so working loads usually include a safety factor of 3 to 5 or more, and anchors must resist the full tension at the cable angle.

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Results are estimates provided for information purposes. They do not replace professional advice.