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Omnikalc

Projectile motion calculator: range, height and flight time

Enter the launch speed, angle and height to get how far a projectile travels, how high it goes and how long it stays in the air.

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Results

Horizontal range

135.4

Maximum height

33.8

Time of flight

2.90 s

Time to the top
1.45 s
Impact speed
45.0
Impact angle below horizontal
45.0 °

Range at other angles

Horizontal rangeMaximum heightTime of flight
15° current67.74.51.06
30° current117.216.92.05
40° current133.328.02.64
45° current135.433.82.90
50° current133.339.73.14
60° current117.250.83.55
75° current67.763.23.96

The path of a thrown object

Once launched, a ball, a stone or a jet of water follows a parabola. Its horizontal speed stays constant, while gravity steadily pulls its vertical speed down at 9.81 m/s² (32.2 ft/s²). Splitting the launch velocity into those two parts gives every property of the flight. The calculator neglects air resistance, which is reasonable for heavy, compact objects at moderate speeds.

The formulas

With launch speed v₀, angle θ and launch height h₀:

  • Horizontal speed vₓ = v₀ × cos θ; vertical speed v_y = v₀ × sin θ
  • Time of flight t = (v_y + √(v_y² + 2g h₀)) ÷ g
  • Range = vₓ × t
  • Maximum height = h₀ + v_y² ÷ (2g), reached after v_y ÷ g seconds
  • From ground level, the range simplifies to v₀² × sin(2θ) ÷ g, largest at 45°.

Worked example: 45 mph at 45° from the ground

  1. 45 mph = 20.1 m/s, so vₓ = v_y = 20.1 × 0.707 = 14.2 m/s.
  2. Time of flight: 2 × 14.2 ÷ 9.81 = 2.90 s.
  3. Range: 14.2 × 2.90 = 41.3 m, or 135 ft.
  4. Maximum height: 14.2² ÷ 19.61 = 10.3 m, or 34 ft, reached after 1.45 s.
  5. The ball lands at 45 mph and 45° below the horizontal, the mirror image of the launch.

Range at other angles (45 mph, from the ground)

Angle Range Max height Flight time
15° 68 ft 4.6 ft 1.06 s
30° 117 ft 17 ft 2.05 s
45° 135 ft 34 ft 2.90 s
60° 117 ft 51 ft 3.55 s
75° 68 ft 63 ft 3.96 s

Complementary angles such as 30° and 60° give the same range from the ground: the higher shot just stays longer in the air.

Launching from a height

From a raised point, the best angle is a little below 45°, because the projectile has extra time to travel forward while it falls. A shot put released at 7 ft is best thrown at about 37 to 42°, depending on speed.

Where air resistance changes the answer

Drag shortens the range and makes the descent steeper than the climb. A baseball hit at 100 mph would fly over 650 ft in a vacuum but only about 400 ft in real air; spin adds lift and changes it again. Use the calculator for physics problems, garden hoses, slow throws and as an upper bound for fast objects.

Practical uses

  • Sports: estimating how speed and angle trade off for a throw, a kick or a jump.
  • Water jets: a fountain or a hose follows the same parabola; the exit speed comes from the pressure.
  • Safety distances: the maximum range at 45° gives the upper bound of where debris or a thrown object can land.

Frequently asked questions

What angle gives the maximum range?

45° when launching from and landing on the same level, ignoring air resistance. From a height, the best angle is slightly lower.

How do you calculate the range of a projectile?

From ground level, range = v² × sin(2θ) ÷ g. At 20 m/s and 45°, that is 400 ÷ 9.81 = 40.8 m.

How do you find the maximum height?

h = (v × sin θ)² ÷ (2g), plus the launch height.

Why do 30° and 60° give the same range?

Because sin(2θ) is the same for complementary angles. The 60° shot goes higher and stays longer in the air.

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Results are estimates provided for information purposes. They do not replace professional advice.