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Omnikalc

Punnett square calculator: offspring genotype and trait probabilities

Cross two parents for one gene and get the chance of each genotype in their children, plus the odds across several children.

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Results

Child is AA

25.0%

Child is Aa (carrier)

50.0%

Child is aa (shows the recessive trait)

25.0%

Classic 1:2:1 cross Two carriers: on average one child in four is aa and three in four show the dominant trait.
Child shows the dominant trait
75.0%
At least one aa child among them
57.8%
No aa child among them
42.2%

Chance of at least one aa child

At least one aa child among themNo aa child among them
1 current25.0%75.0%
2 current43.8%56.3%
3 current57.8%42.2%
4 current68.4%31.6%
5 current76.3%23.7%
6 current82.2%17.8%

Predicting a child’s genotype

A Punnett square, named after British geneticist Reginald Punnett, is a simple grid that shows every way two parents’ alleles can combine. Each parent passes on one of their two copies of a gene, at random. For a single gene with a dominant allele A and a recessive allele a, the square gives the probability of each genotype in a child.

How it works

  • Each parent’s genotype is AA, Aa or aa.
  • An AA parent always passes A, an aa parent always passes a, and an Aa parent passes either with a 50% chance.
  • P(AA) = P(A from parent 1) × P(A from parent 2)
  • P(aa) = P(a from parent 1) × P(a from parent 2)
  • P(Aa) = everything else
  • For several children: P(at least one aa) = 1 − (1 − P(aa))^n

Worked example: two carriers

Both parents are Aa carriers of a recessive trait.

A a
A AA Aa
a Aa aa
  1. AA: 25%, Aa: 50%, aa: 25%.
  2. 75% of children show the dominant trait; 25% show the recessive one.
  3. With 3 children, the chance that at least one is aa is 1 − 0.75³ = 57.8%.
  4. The chance that none of the three is aa is 42.2%.

All six crosses

Parents AA Aa aa
AA × AA 100% 0% 0%
AA × Aa 50% 50% 0%
AA × aa 0% 100% 0%
Aa × Aa 25% 50% 25%
Aa × aa 0% 50% 50%
aa × aa 0% 0% 100%

Every child is a new draw

Probabilities apply to each child independently. Two carrier parents who already have an affected child still face a 25% chance with the next one; the earlier result does not use up the odds.

Beyond one gene

  • Two genes (dihybrid crosses) give a 4 × 4 square and the classic 9:3:3:1 ratio when the genes are independent.
  • Incomplete dominance, as in snapdragon flower color, makes Aa look intermediate.
  • Co-dominance and multiple alleles, as in the ABO blood groups, need more than two letters.
  • Sex-linked traits such as red-green color blindness depend on which parent passes the X chromosome.
  • Most human traits, like height or eye color, involve many genes and the environment, so a single Punnett square cannot predict them.

For questions about inherited conditions in a family, a genetic counselor can interpret test results and actual risks.

Frequently asked questions

What is the chance two carriers have an affected child?

25% for each child. Two Aa parents give AA, Aa and aa children in a 1:2:1 ratio, so one child in four is aa on average.

How do you read a Punnett square?

Write one parent's alleles across the top and the other's down the side, then combine them in each box. Each of the four boxes has a 25% chance.

If the first child is affected, is the next one less likely to be?

No. Each pregnancy is independent, so the chance stays 25% for every child of two carriers.

What does a carrier × affected cross give?

Aa × aa gives 50% Aa carriers and 50% aa children who show the recessive trait.

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Results are estimates provided for information purposes. They do not replace professional advice.