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Omnikalc

Resistor calculator: total resistance in series and in parallel

Enter up to four resistors to get their total resistance connected in series and in parallel.

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Results

Total in series

790.00

Total in parallel

59.98

Total conductance in parallel
16.673 mS
Resistors counted
3

Effect of the fourth resistor

Total in seriesTotal in parallel
R4 = 0 Ω current790.0059.98
R4 = 10 Ω current800.008.57
R4 = 100 Ω current890.0037.49
R4 = 1,000 Ω current1,790.0056.58
R4 = 10,000 Ω current10,790.0059.62

Series and parallel

Resistors can be connected end to end (in series) or side by side (in parallel). The arrangement changes the total, or equivalent, resistance that the rest of the circuit sees.

  • Series: the same current flows through each resistor and the resistances add: R = R1 + R2 + R3 + …. The total is always larger than the largest resistor.
  • Parallel: each resistor sees the same voltage and the currents add. The conductances (1 ÷ R) add: 1 ÷ R = 1 ÷ R1 + 1 ÷ R2 + 1 ÷ R3 + …. The total is always smaller than the smallest resistor.

Worked example: 100 Ω, 220 Ω and 470 Ω

  1. In series: 100 + 220 + 470 = 790 Ω.
  2. In parallel: 1 ÷ 100 + 1 ÷ 220 + 1 ÷ 470 = 0.01 + 0.004545 + 0.002128 = 0.016673 S.
  3. R = 1 ÷ 0.016673 = 59.98 Ω, below the smallest resistor of 100 Ω.

Shortcuts for parallel resistors

  • Two resistors: R = (R1 × R2) ÷ (R1 + R2), the “product over sum”. 100 Ω and 220 Ω give 22,000 ÷ 320 = 68.75 Ω.
  • n identical resistors: R ÷ n. Four 1 kΩ resistors in parallel make 250 Ω.
  • One very large resistor in parallel barely changes the total, while a small one dominates it.

Effect of adding a fourth resistor

R4 Series total Parallel total
none 790 Ω 59.98 Ω
10 Ω 800 Ω 8.57 Ω
100 Ω 890 Ω 37.49 Ω
1 kΩ 1,790 Ω 56.58 Ω
10 kΩ 10,790 Ω 59.62 Ω

Mixed circuits

Real circuits often combine both. Solve them step by step: replace each group of resistors in parallel by its equivalent, then add up the series parts, and repeat until a single value remains. For example, a 100 Ω resistor in series with two 220 Ω resistors in parallel gives 100 + 110 = 210 Ω.

Practical uses

  • Getting a value you don’t have: two 1 kΩ resistors in series make 2 kΩ; in parallel, 500 Ω.
  • Sharing power: several resistors in parallel spread the heat. Two 1 W resistors of 200 Ω in parallel act as a 100 Ω resistor rated 2 W.
  • LED strings: LEDs with their resistor in series share the same current; branches in parallel each need their own resistor.
  • Speakers: two 8 Ω speakers in parallel present 4 Ω to the amplifier; in series, 16 Ω. Check that your amplifier supports the result.

Capacitors and inductors

Inductors follow the same rules as resistors. Capacitors do the opposite: capacitances add in parallel, and their reciprocals add in series.

Frequently asked questions

How do you calculate resistors in series?

Add them: R = R1 + R2 + R3. 100 Ω, 220 Ω and 470 Ω in series make 790 Ω.

How do you calculate resistors in parallel?

Add their reciprocals and invert: 1/R = 1/R1 + 1/R2 + …. For two resistors, R = R1 × R2 ÷ (R1 + R2).

Is parallel resistance always smaller?

Yes, the total in parallel is always smaller than the smallest resistor, because each branch adds a path for the current.

What is the resistance of two equal resistors in parallel?

Half of one of them: two 1 kΩ resistors in parallel make 500 Ω.

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Results are estimates provided for information purposes. They do not replace professional advice.